18. 4Sum [LeetCode]
Given an array S of n integers, are there elements a,b,c, and d in S such that a+b+c+d= target? Find all unique quadruplets in the array which gives the sum of target.
Note:The solution set must not contain duplicate quadruplets.
For example, given array S = [1, 0, -1, 0, -2, 2], and target = 0.
A solution set is: [ [-1, 0, 0, 1], [-2, -1, 1, 2], [-2, 0, 0, 2] ]
注意每一层的去重条件为排除每一层的第一个元素,不一定是index为0的元素。类似于DFS里的去重。
class Solution {
public List<List<Integer>> fourSum(int[] nums, int target) {
List<List<Integer>> results = new ArrayList<>();
if (nums == null || nums.length < 4) {
return results;
}
Arrays.sort(nums);
for (int i = 0; i < nums.length - 3; i++) {
if (i != 0 && nums[i] == nums[i - 1]) {
continue;
}
for (int j = i + 1; j < nums.length - 2; j++) {
if (j != i + 1 && nums[j] == nums[j - 1]) {
continue;
}
int start = j + 1;
int end = nums.length - 1;
while (start < end) {
if (start != j + 1 && nums[start] == nums[start - 1]) {
start++;
continue;
}
if (end != nums.length - 1 && nums[end] == nums[end + 1]) {
end--;
continue;
}
int sum = nums[i] + nums[j] + nums[start] + nums[end];
if (sum < target) {
start++;
} else if (sum > target) {
end--;
} else {
List<Integer> quad = new ArrayList<Integer>();
quad.add(nums[i]);
quad.add(nums[j]);
quad.add(nums[start]);
quad.add(nums[end]);
results.add(quad);
start++;
end--;
}
}
}
}
return results;
}
}